CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A mass is suspended from the end of a spring. When the system is oscillating the amplitude of oscillation is 4 cm and the maximum kinetic energy of oscillation of the system is 1 joule. Then the force constant of the spring is:

A
2500 N/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1250 N/m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
500 N/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
250 N/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1250 N/m
By energy conservation, maximum kinetic energy is equal to the potential energy of the spring at maximum elongation since kinetic energy is zero at maximum elongation.

Hence, 1=12k(0.04)2

k=1250 N/m



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy in SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon