A mass M is broken into two parts of masses $m_{1}$ and $m_{2}$ . How are $m_{1}$ and $m_{2}$ related so that force of gravitational attraction between the two parts is maximum?

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Solution

Let mass of one part be $x$
then $F = \frac{G x (M - x)}{r^{2}} F^{^{'}} = \frac{G}{R^{2}} (M - 2 x) \Rightarrow M - 2 m = 0$
$x = \frac{M}{2}$ is point of maxima.

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A mass M is broken into two parts of masses m1 and m2. How are m1 and m2 related so that force of gravitational attraction between the two parts is maximum?

Let mass of one part be x then F=Gx(M−x)r2F′=GR2(M−2x)⇒M−2m=0x=M2 is point of maxima.

A mass M is broken into two parts of masses $m_{1}$ and $m_{2}$ . How are $m_{1}$ and $m_{2}$ related so that force of gravitational attraction between the two parts is maximum?

Let mass of one part be $x$
then $F = \frac{G x (M - x)}{r^{2}} F^{^{'}} = \frac{G}{R^{2}} (M - 2 x) \Rightarrow M - 2 m = 0$
$x = \frac{M}{2}$ is point of maxima.