A mass M is lowered with the help of a string by a distance h at a constant acceleration g -2 - The work done by string will beA- M g h-2B- -M g h-2C- 3 M g h-2D- -3 M g h-2

Tension in the string, T = M (g a) = M ( g g/2 ) = Mg/2 W = Force × Displacement = Mgh/2 Negative sign is because tension is in the upward direction ...

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Standard XII

Physics

Gravtiational PE

A mass M is l...

Question

A mass M is lowered with the help of a string by a distance h at a constant acceleration $\frac{g}{2}$ . The work done by string will be

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Solution

The correct option is B

Tension in the string,

$T = M (g - a) = M (g - \frac{g}{2}) = M g / 2$

$W = F o r c e \times D i s p l a c e m e n t = - \frac{M g h}{2}$

Negative sign is because tension is in the upward direction and displacement is in the downward direction.

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A mass M is lowered with the help of a string by a distance h at a constant acceleration g2. The work done by string will be

The correct option is B Tension in the string, T=M(g−a)=M(g−g2)=Mg/2 W= Force×Displacement =−Mgh2 Negative sign is because tension is in the upward direction and displacement is in the downward direction.

A mass M is lowered with the help of a string by a distance h at a constant acceleration $\frac{g}{2}$ . The work done by string will be

The correct option is B

Tension in the string,

$T = M (g - a) = M (g - \frac{g}{2}) = M g / 2$

$W = F o r c e \times D i s p l a c e m e n t = - \frac{M g h}{2}$

Negative sign is because tension is in the upward direction and displacement is in the downward direction.