A mass m is moving with a constant velocity v along a line parallel to X− axis, away from origin. Then, its angular momentum with respect to the origin
A
is zero
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B
remains constant
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C
goes on increasing
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D
goes on decreasing
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Solution
The correct option is B remains constant Particle is moving with a constant velocity →v parallel to X−axis, then the position vector →r of particle is changing with respect to origin, but not the perpendicular distance about origin O.
⇒⊥ distance of particle about origin=constant=y ⇒Angular momentum about O: |→L|=mvr⊥=mvy ∴|→L|=constant
Direction of →L is governed by direction of (→r×m→v), so it is also constant, since →L is coming along −veZ-axis, i.e perpendicularly inwards for the plane X−Y.