You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Simple Harmonic Oscillation

A mass M is...

Question

A mass $M$ is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic motion with time period $T$ . If the mass is increased to $^{'} m^{'}$ then the time period becomes $(\frac{5 T}{4})$ . The ratio $(\frac{m}{M})$ is

\frac{9}{16}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{25}{16}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{4}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{25}{16}$
$T_{1} = 2 π \sqrt{\frac{m_{1}}{K}}$
$T = 2 π \sqrt{\frac{M}{K}}; \frac{5 T}{4} = 2 π \sqrt{\frac{m}{K}}$
ratio $\frac{m}{M} = \frac{25}{16}$

Suggest Corrections

Similar questions

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T. If the mass is increased by m then the time period becomes $(\frac{5}{4} T)$ . The ratio of $\frac{m}{M}$ is

Q. A mass

M

is suspended from a spring of negligible mass. The spring is pulled a little then released, so that the mass executes simple harmonic motion of time period

T .

If the mass is increased by

m,

the time period becomes

\frac{5 T}{3}

. The ratio of

\frac{m}{M}

is:

Q. A mass

M

is suspended form a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period

T

. If the mass is increased by

m

then the time period becomes

(\frac{5}{4} T)

. Find the ratio

\frac{m}{M}

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released, so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes $\frac{5 T}{3}$ . Then the ratio of $\frac{m}{M}$ is

Q. A mass

M

is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes

S H M

of time period

T

. If the mass is increased by m, the time period becomes

5 T / 3

. then the ratio of

m / M

Join BYJU'S Learning Program

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic motion with time period T. If the mass is increased to ′m′ then the time period becomes (5T4) . The ratio(mM) is

The correct option is B 2516T1=2π√m1KT=2π√MK;5T4=2π√mKratio mM=2516

A mass $M$ is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic motion with time period $T$ . If the mass is increased to $^{'} m^{'}$ then the time period becomes $(\frac{5 T}{4})$ . The ratio $(\frac{m}{M})$ is

The correct option is B $\frac{25}{16}$
$T_{1} = 2 π \sqrt{\frac{m_{1}}{K}}$
$T = 2 π \sqrt{\frac{M}{K}}; \frac{5 T}{4} = 2 π \sqrt{\frac{m}{K}}$
ratio $\frac{m}{M} = \frac{25}{16}$