Question

A mass ${}^{\prime }{m}^{\prime }$ moves with velocity $v=\sqrt{3}m/s$ and collides with another mass $2m$ initially at rest. After collision first mass move with velocity $\frac{v}{\sqrt{3}}$ in the direction perpendicular to initial direction of motion. Speed of second mass (in m/s) after collision is ____________.

Answer 1

By momentum conservation Horizontal .

$m\sqrt{3}=2m{u}_1{u}_1=\frac{\sqrt{3}}{2}$

vertical $m\times 1-2m{u}_2=0$

$u_2=\frac{1}{2}u=\sqrt{u_1^2+u_2^2}=\sqrt{\frac{3}{4}+\frac{1}{4}}=1m/s$