A mass $m$ rests at height $2 h$ above the floor, while a mass $2 m$ rests at a height of $3 h$ . How much more gravitational potential energy does $2 m$ have compared to $m$ if the gravitational field is uniform?

0

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m g h

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2 m g h

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3 m g h

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4 m g h

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Solution

The correct option is E $4 m g h$
The gravitational potential energy of mass $m$
$P . E_{1} = m g (2 h) = 2 m g h$
Gravitational potential energy of mass $2 m$
$P . E_{2} = (2 m) g (3 h) = 6 m g h$
$⟹$ $Δ P . E = P . E_{2} - P . E_{1}$
$= 6 m g h - 2 m g h = 4 m g h$

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