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Question

A mass m slides down a plane inclined at an angle α to the horizontal. The height of the inclined plane is h and the coefficient of friction over both surface is μ. Then the distance that it will move on the horizontal plane after covering the entire length of the inclined plane.

A
h- htanα
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B
hμ - htanα
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C
hμ - h
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D
hμ - 1tanα
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Solution

The correct option is B hμ - htanα

Block starts from A and comes to rest again at C. Along the path, loss in potential energy = work done against friction.

mgh = WAB + WBC = μmg cos α. h/sinα + μmg l

or l = hμ - htanα


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