Question

A mass m slips along a smooth hemispherical surface of radius R starting from rest at the top as shown.

The velocity of the mass at the bottom of the surface is

• A. $\sqrt{Rg}$
• B. $\sqrt{2Rg}$
• C. $2\sqrt{\pi Rg}$
• D. $2\sqrt{\pi Rg}$

Answer 1

The correct option is B

$\sqrt{2Rg}$

By applying law of conservation of energy

mgR = $\frac{1}{2}m{v}^2$

$\Rightarrow v=\sqrt{2Rg}$