A mass of 0.5 kg moving with a speed of 1.5ms−1 on a horizontal smooth surface, collides with a nearly weightless spring of force constant k=50Nm−1. The maximum compression of the spring would be
A
0.15 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1.6 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.23 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.4 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D 0.15 m By the law of conservation of energy. Kinetic energy of mass = energy stored in spring 12mv2=12kx2 x2=mv2k The maximum compression of the spring x=√mv2k x=√0.5×1.5×1.550=0.15m