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Standard X

Physics

Apparent Frequency

A mass of 1...

Question

A mass of $1 k g$ attached to the bottom of a spring has a certain frequency of vibration. The following mass has to be added to it in order to reduce the frequency by half

1 k g

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2 k g

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3 k g

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4 k g

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Solution

The correct option is C $3 k g$
frequency $ω$
$ω = \sqrt{\frac{k}{m}}$
$m = 1 K g$
In order to reduce the frequency to hallf
$\frac{ω}{2} = \sqrt{\frac{k}{m}}$
$\frac{1}{2} \sqrt{\frac{k}{1}} = \sqrt{\frac{k}{m}}$
$m = 4 K g$
mass that is to be added= $4 - 1 = 3 K g$

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A mass of 1 kg attached to the bottom of a spring has a certain frequency of vibration. The following mass has to be added to it in order to reduce the frequency by half

The correct option is C 3 kgfrequency ωω=√kmm=1KgIn order to reduce the frequency to hallfω2=√km 12√k1=√kmm=4Kgmass that is to be added=4−1=3Kg

A mass of $1 k g$ attached to the bottom of a spring has a certain frequency of vibration. The following mass has to be added to it in order to reduce the frequency by half

The correct option is C $3 k g$
frequency $ω$
$ω = \sqrt{\frac{k}{m}}$
$m = 1 K g$
In order to reduce the frequency to hallf
$\frac{ω}{2} = \sqrt{\frac{k}{m}}$
$\frac{1}{2} \sqrt{\frac{k}{1}} = \sqrt{\frac{k}{m}}$
$m = 4 K g$
mass that is to be added= $4 - 1 = 3 K g$