A mass of $1 k g$ is placed at $(1 m, 2 m, 0)$ Another mass of $2 k g$ is placed at $(3 m, 4 m, 0) .$ The moment of inertia of both the masses about z-axis is (50+x). The value of x is:

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Solution

$I = (1) {[\sqrt{(1)^{2} + (2)^{2}}]}^{2} + 2 [{\sqrt{(3}}^{2} + (4)^{2}]^{2}$
$= 55 k g - m^{2}$

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