Question

A mass of 1 kg is suspended from a spring of force constant 400 N, executing SHM total energy of the body is 2J, then maximum acceleration of the spring will be

• A. $4m/s^2$
• B. $40m/s^2$
• C. $200m/s^2$
• D. $400m/s^2$

Answer 1

Answer: (B)

$40m/s^2$

$\omega =\sqrt{\frac{k}{m}}=\sqrt{400}=20\frac{1}{2}m{\omega }^2{A}^2=2\Rightarrow A=\frac{1}{10}m$

Acceleration $=A{\omega }^2=\frac{400}{10}m/s^2=40m/s^2$