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Standard XII

Physics

Defining Kinetic Energy

A mass of 1...

Question

A mass of $1 k g$ is thrown up with a velocity of $100 m / s$ . After $5$ seconds, it explodes into two parts. One part of mass $400 g$ moves down with a velocity $25 m / s$ . The velocity of other part is (Take $g = 10 m s^{- 2}$ )

40 m / s ↑

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40 m / s ↓

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100 m / s ↑

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60 m / s ↓

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Solution

The correct option is A $40 m / s ↑$
After 5sec velocity of the 1kg will be $v = 100 - g t = 100 - 10 \times 5 = 100 - 50 = 50 m / s e c$
By conservation of momentum $M_{f} = M_{i}$
$⟹ 1 \times 50 = 0.6 v - 0.4 \times 25$
$⟹ 0.6 v = 60$
$∴ v = 100 m / s$

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A mass of 1 kg is thrown up with a velocity of 100 m/s. After 5 seconds, it explodes into two parts. One part of mass 400 g moves down with a velocity 25m/s. The velocity of other part is (Take g=10 ms−2)

The correct option is A 40m/s↑After 5sec velocity of the 1kg will be v=100−gt=100−10×5=100−50=50m/secBy conservation of momentum Mf=Mi⟹1×50=0.6v−0.4×25⟹0.6v=60∴v=100m/s

A mass of $1 k g$ is thrown up with a velocity of $100 m / s$ . After $5$ seconds, it explodes into two parts. One part of mass $400 g$ moves down with a velocity $25 m / s$ . The velocity of other part is (Take $g = 10 m s^{- 2}$ )

The correct option is A $40 m / s ↑$
After 5sec velocity of the 1kg will be $v = 100 - g t = 100 - 10 \times 5 = 100 - 50 = 50 m / s e c$
By conservation of momentum $M_{f} = M_{i}$
$⟹ 1 \times 50 = 0.6 v - 0.4 \times 25$
$⟹ 0.6 v = 60$
$∴ v = 100 m / s$