You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Why Com Is an Important Point

A mass of 1...

Question

A mass of $10 g$ moving horizontally with a velocity of $100 c m s^{- 1}$ strikes a pendulum bob of same mass. The two masses after collision stick together. What will be the maximum height reached by the system now? (Take $g = 10 m s^{- 2}$ )

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

.125 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2.5 c m$
Value of g in cgs is $1000 c m / s^{2}$ .
Kinetic energy of mass of $10 g$ is converted into potential energy of the system
$∴ \frac{1}{2} m_{1} v_{1}^{2} = (m_{1} + m_{2}) g h$
or $h = \frac{m_{1} v_{1}^{2}}{2 (m_{1} + m_{2}) g} = \frac{10 \times {(100)}^{2}}{2 (10 + 10) \times 1000} = 2.5 c m$

Suggest Corrections

Similar questions

A mass of 10 gm moving with a velocity of 100 cm/s strikes a pendulum bob of mass 10 gm. The two masses stick together. The maximum height reached by the system now is $(g = 10 m / s^{2})$

Q. A mass of 10 gm. moving horizontally with a velocity of

100 c m / s e c

, strikes the bob of a pendulum and sticks to it. The mass of the bob is also 10 gm. The maximum height to which the system can be raised is (

g = 10 m / s e c^{2}

)

Q. A ball of mass

^{'} m^{'}

moving with a horizontal velocity

^{'} v^{'}

strikes the bob of a pendulum at rest. Mass of the bob of the pendulum is also

^{'} m^{'}

. During this collision the ball sticks with the bob of the pendulum. The height to which the combined mass rises: (g=acceleration due to gravity)

Q. A steel ball having mass

100 g

is moving with velocity

20 m/s

. In the same direction, a ball of clay having mass

20 g

is moving with velocity

10 m/s

. If after some time, both balls collide and stick together, what will be the speed of steel ball after collision?

Q. The bob

A

of a pendulum of mass

m

released from horizontal to the vertical hits another bob

B

of the same mass at rest on a table as shown in figure. If the length of the pendulum is

1 m

, what is the speed with which bob

B

starts moving. (Neglect the size of the bobs and assume the collision to be elastic) (Take

g = 10 m s^{- 2})

Join BYJU'S Learning Program

A mass of 10g moving horizontally with a velocity of 100cms−1 strikes a pendulum bob of same mass. The two masses after collision stick together. What will be the maximum height reached by the system now? (Take g=10ms−2)

The correct option is C 2.5cmValue of g in cgs is 1000cm/s2.Kinetic energy of mass of 10g is converted into potential energy of the system∴12m1v21=(m1+m2)ghor h=m1v212(m1+m2)g=10×(100)22(10+10)×1000=2.5cm

A mass of $10 g$ moving horizontally with a velocity of $100 c m s^{- 1}$ strikes a pendulum bob of same mass. The two masses after collision stick together. What will be the maximum height reached by the system now? (Take $g = 10 m s^{- 2}$ )