CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Work Energy Theorem Application

A mass of 2...

Question

A mass of $2.5 k g$ is hung on a steel wire. This increase $0.25 c m$ in its length. Determine the work done to pull the wire. $(g = 10 m / s^{2})$

Open in App

Solution

Given that,

Mass $m = 2.5 k g$

Length $l = 0.25 c m$

Now, the work done is

$W = m g h$

$W = 2.5 \times 10 \times 0.25 \times 10^{- 2}$

$W = 0.0625 J$

Hence, the work done is $0.0625 J$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A steel wire 2 m long is suspended from the ceiling. When a mass is hung at its lower end, the increase in length recorded is 1 cm. Determine the strain in the wire.

Q. A steel wire

2 m

long is suspended from the ceiling. When a mass is hung at its lower end, the increase in length recorded is

1 cm

. Determine the strain in the wire.

Q. A steel wire of length

4 m

is stretched by a force of

100 N

. The work done to increase the length of the wire by

2 m m

Q. A copper wire and a steel wire of the same length and same cross section are joined end to end to form a composite wire. The composite wire is hung from a rigid support and a load is suspended from the other end. If the increase in length of the composite wire is

2.4 m m

, then the increase in lengths of steel and copper wires are:

(Y_{c u} = 10 \times 10^{10} N / m^{2}, Y_{s t e e l} = 2 \times 10^{11} N / m^{2})

Q. A wire suspended vertically is stretched by a

20 k g f

. Applied to its free end. The increase in length of the wire is

2 m m

. The energy stored in the wire is

(g = 10 m s^{- 2})

:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Conservative Forces and Potential Energy

PHYSICS

Watch in App

explore_more_icon

Explore more

Work Energy Theorem Application

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon