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Standard XII

Physics

Motional EMF

A mass of 2...

Question

A mass of $2 k g$ tied to a string of $1 m$ length is rotating in a vertical circle with a uniform speed of $4 m s^{- 1}$ . The tension in the string will be $52 N$ , when the mass is at[ $g = 10 m s^{- 2}$ ]:

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Solution

The correct option is A bottom
$T - m g s i n θ = \frac{m v^{2}}{R}$ ( $θ$ is the angle from the horizontal line at any point on the circle)
Thus we get
$52 - 2 \times 10 \times s i n θ = \frac{2 \times 16}{1}$
Thus $θ = 90^{o}$
Thus the tension of 52 N would occur at the $b o t t o m m o s t p o i n t$ .

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A mass of 2 kg tied to a string of 1 m length is rotating in a vertical circle with a uniform speed of 4 ms−1. The tension in the string will be 52 N, when the mass is at[g=10ms−2]:

The correct option is A bottomT−mgsinθ=mv2R (θ is the angle from the horizontal line at any point on the circle)Thus we get52−2×10×sinθ=2×161Thus θ=90oThus the tension of 52 N would occur at the bottom most point.

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