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Question

A mass of 200gm has initial velocity Vi=2^i+3^j and final velocity 2^i3^j. Find magnitude of change in momentum.

A
|Δp|=3.84
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B
|Δp|=3.04
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C
|Δp|=1.44
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D
|Δp|=2.04
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Solution

The correct option is C |Δp|=1.44
Given,

|ΔP|=1.44

Given,

m=200gm=0.2kg

Initial velocity, $

vi=2^i+3^j

Final velocity, vf=2^i3^j

Change in magnitude, ΔP=m(vfvi)

ΔP=0.2(4^i6^j)

ΔP=0.8^i1.2^j in vector form.

The magnitude of change in momentum is

|ΔP|=(0.8)2+(1.2)2

|ΔP|=1.44

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