A mass of 5 kg is suspended from a spring of stiffness 4000 N/m. The system is fitted with a damper with a damping ratio of 0.2. The mass is pulled down 50 mm and then released. Calculate the damped frequency.
The natural
frequency is given by
fn=12π√kM⇒fn=12π√40005=4.5Hz
The
damped frequency is given by
f=fn√1−δ2=4.5×√1−0.04=4.41Hz