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Question

A mass of 8 kg rests on a rough horizontal surface and is attached to a mass of 4 kg kept hanging downwards by a string passing over a smooth light pulley. If μ = 0.5, find the acceleration of the system and the tension in the string. (g = 9.8 m/s2)(1.31 m/s, 33.96 N)

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Solution

mgT=ma

4×10T=4a(i)

Tf=8a.

TμN=8a.

T0.5×8×10=8a

T40=8a(ii)

a=0system is not moving.

Soa=0,

T=39.20N


1007140_1059243_ans_4b22d82f47df47e6880d41a4c076f42a.PNG

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