Question

A mass of M of 100 kg is suspended with the use of strings A, B and C as shown in the figure, where W is the vertical wall and R is a rigid horizontal rod. The tension in the string B is

• A. 100g N
• B. zero
• C. 100$\sqrt{2}$g N
• D. $\frac{100}{\sqrt{2}}$g N

Answer 1

The correct option is A 100g N

$Tcos{45}^o=T^{\prime }$

$Tsin{45}^o=Mg=100\times 10=100g$

$\frac{T}{\sqrt{2}}=100g\Rightarrow T=100\sqrt{2}gN$

$T^{\prime }=Tcos{45}^o=100\sqrt{2}g\times \frac{1}{\sqrt{2}}=100gN$
Hence the correct option is $\left(A\right)$