Question

A mass $\text{M}$ is lowered with the help of a string by a distance $\text{x}$ at a constant acceleration $\frac{g}{2}$. The magnitude of work done by the string will be

• A. $\text{Mgx}$
• B. $\frac{1}{2}{\text{Mgx}}^2$
• C. $\frac{1}{2}\text{Mgx}$
• D. ${\text{Mgx}}^2$

Answer 1

The correct option is C $\frac{1}{2}\text{Mgx}$

$Mg-T=\frac{Mg}{2}\text{or}T=\frac{Mg}{2}$
or, magnitude of work done $=T\times x=\frac{Mgx}{2}$