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Question

A massless spring balance is attached to 2 kg trolley and is used to pull the trolley along a flat surface as shown in the fig. The reading on the spring balance remains at 10 kg during the motion. The acceleration of the trolley is: (Use g=9.8 ms−2)
293297_9952c242e4fc4867a96ee14b11e63aaf.png

A
4.9ms2
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B
9.8ms2
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C
49ms2
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D
98ms2
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Solution

The correct option is C 49ms2
We know that spring will measure the force acting on it, either compression or tension.
Here tensile force is acting on it so spring force(kx)=force(F)
F=mg=10×9.81=98.1N
By Newton's second law, F=ma

a=Fm=98.12=49.05 ms2

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