Question

A massless uniform rod is subjected to force F at its free end as shown in figure. The ratio of tensile stress at plane $P_1$ to stress at $P_2$ is

• A. $1:2$
• B. $\sqrt{2}:1$
• C. $1:4$
• D. $3:2$

Answer 1

The correct option is C $1:4$

$\begin{array}{c}\text{Let Area of cross section be}A\\ \text{Stress at}{P}_2=\frac{F}{A}\\ \text{Stress at}{P}_1=\frac{F{\cos }^2\theta }{A}\\ \text{Stressat}{P}_1:P_2={\cos }^2\theta \\ ={\cos }^2{60}^{\circ }\\ =1:4\end{array}$