Question

A match box measures $4$ $cm$ $\times 2.5$ $cm$ $\times 1.5$ $cm$. What will be the volume of a packet containing $12$ such boxes?

Answer 1

Given:

$l=4$, $b=2.5$, $h=1.5$

$V=l\times b\times h$

$=4\times 2.5\times 1.5$cm${}^2$

$=15$cm${}^3$

Volume of $12$ matchboxes

$=12\times 15$cm${}^3$

$=180$cm${}^3$