Question

A matchbox measures $4cm\times 2.5cm\times 1.5cm.$ What will be the volume of a packet containing $12$ such boxes?

Answer 1

VOLUME:

The space occupied by an object is called the volume of the particular object.

Volume is always measured in cubic unit.

Given:

Dimensions of the matchbox $=4\text{cm}\times 2.5\text{cm}\times 1.5\text{cm}$

So, $l=4\text{cm}$, $b=2.5\text{cm}$ and $h=1.5\text{cm}$

Volume of cuboid $=(l\times b\times h)$

Volume of one matchbox = Volume of cuboid

Volume of one matchbox $=4\times 2.5\times 1.5$

$=15{\text{cm}}^3$

Volume of a packet containing $12$ such boxes $=12\times$ volume of one match box

$=(12\times 15){\text{cm}}^3=180{\text{cm}}^3$

Hence, the volume of a packet containing $12$ such boxes $=180$ ${\text{cm}}^3$