Question

A material has poisson's ratio of 0.5. If a uniform rod suffers a longitudinal strain of 2 x 10${}^{-3}$ the percentage increase in its volume is :

• A. 2%
• B. 0.5%
• C. 4%
• D. 0%

Answer 1

The correct option is D 0%

The volume change of a material due to the strain is related to the poisson's ration by the relation:

$\Delta V/V=(1-2\times \sigma )\Delta L/L$ where, $\sigma$ is the poisson's ratio of the material.

In this case the term in the bracket of RHS is zero since $\sigma$ is 0.5. So percentage volume change is 0%.