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Question
A mathematician born in the first half of the 19th century was x years old in the year x2. He was born in
A mathematician born in the first half of the 19th century was x years old in the year x2. He was born in
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Solution
The correct option is D 1806
The man born between 1800 and 1850 which is a perfect square.
The perfect square number is 43=1849 (Since42=1764 and 44=1936 )
So in the year 1849 the man was 43 years old.
Which shows the year of born is 1849−43=1806.
The man born between 1800 and 1850 which is a perfect square.
The perfect square number is 43=1849 (Since42=1764 and 44=1936 )
So in the year 1849 the man was 43 years old.
Which shows the year of born is 1849−43=1806.
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