A Matrix of any order can be a hermitian matrix

True

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False

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Solution

The correct option is B
False

Only square matrices can be Hermitian Matrices. Because when we take the transpose only square matrices maintain the order which is necessary for equality of matrices and conjugate does not change the order.

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Similar questions

In a square matrix of order 4, the element $a_{33}$ = 33. This square matrix cannot be skew hermitian.

If A is a square matrix then $A -^{T}$ is a skew hermitian matrix.

A^{θ} = A

a_{i j} =_{j i}

A^{θ} = - A

a_{i j} = -_{j i}

A^{θ}

\to

f (A) = {\begin{matrix} 1 A i s h e r m i t i a n - 1 A i s s k e w h e r m i t i a n \end{matrix}

f (A - A^{θ}) =

A matrix with diagonal elements as complex numbers with imaginary part not 0 can never be Hermitian matrix

If A is a square matrix then $A -^{T}$ is a skew hermitian matrix.

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