Question

A mean annual runoff of $2m^3/s$ from a catchment of area $10k{m}^2$ represents an effective rainfall of nearly:

• A. 530 cm
• B. 590 cm
• C. 630 cm
• D. 658 cm

Answer 1

The correct option is C 630 cm

$Q=2m^3/s$
$=2\times 3600\times 24\times 365m^3/yr$
$=63.072\times {10}^6{m}^3/yr$
$A=10k{m}^2=10\times {10}^6{m}^2$
$\therefore \text{Annual volume}$
$=10\times {10}^{6}y=63.072\times {10}^6$
$\Rightarrow y=6.3072m=630.72cm$