Let ABC be a triangle with a mid-point D on BC.
Therefore, BD = DC
Let AE be the altitude from A on BC.
Now, ar(∆ABD) = × base × height
= × BD × AE
Also, ar(∆ACD) = × base × height
= × CD × AE
= × BD × AE (∵ BD = CD)
= ar(∆ABD)
Hence, a median of a triangle divides it into two triangles of equal area.