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Question

# A medium is divided into region I and II about x = 0 plane, as shown in the figure below. An electromagnetic wave with electric field →E1=4^ax+^3ay+5^az is incident normally on the interface from region-I. The electric field →E2 in region-II at the interface is

A

E2=E1

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B

4^ax+0.75^ay1.25^az

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C

3^ax+3^ay+5^az

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D
3^ax+3^ay+5^az
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Solution

## The correct option is C 3^ax+3^ay+5^az Ans : (c) →Et1=3^ay+5^az=→Et2 →Dn1=→Dn2 ∈2→En2=∈1→En1 →En2=3×4^ax4=3^ax ∴→E2=→Et2+→En2 =3^ay+5^az+3^ax

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