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Question

A medium is divided into region I and II about x = 0 plane, as shown in the figure below. An electromagnetic wave with electric field E1=4^ax+^3ay+5^az is incident normally on the interface from region-I. The electric field E2 in region-II at the interface is


A

E2=E1

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B

4^ax+0.75^ay1.25^az

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C

3^ax+3^ay+5^az

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D
3^ax+3^ay+5^az
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Solution

The correct option is C

3^ax+3^ay+5^az


Ans : (c)
Et1=3^ay+5^az=Et2

Dn1=Dn2
2En2=1En1

En2=3×4^ax4=3^ax

E2=Et2+En2

=3^ay+5^az+3^ax


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