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Strength of Materials

Strain Energy due to Gradually Applied Load and Shear Stress

A member havi...

Question

A member having length L, cross-sectional area A and modulus of elasticity E is subjected to an axial load W. The strain energy stored in this member is

A

\frac{W L^{2}}{A E}

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B

\frac{W L^{2}}{2 A E}

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C

\frac{W^{2} L}{2 A E}

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D

\frac{W^{2} L}{A E}

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Solution

The correct option is C $\frac{W^{2} L}{2 A E}$
$S t r a i n e n e r g y = \frac{1}{2} W Δ = \frac{W^{2} L}{2 A E}$

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