A merchant borrowed Rs3500 from two money lenders. For one loan he paid 14% p.a and for other 18% p.a. the interest paid for one year was Rs525. How much did he borrow at 18%p.a?

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Solution

Let the money borrowed at 14℅ be $X$
Then money borrowed at 18% is $3500 - X$
According to question, $X \times \frac{14}{100} +$ $(3500 - X) \times \frac{18}{100} = 525$
On solving this we get $X = 2625$ and $3500 - X = 875$
So,he borrow $₹ 875$ at rate of $18 ℅ p . a .$

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A merchant borrowed Rs3500 from two money lenders. For one loan he paid 14% p.a and for other 18% p.a. the interest paid for one year was Rs525. How much did he borrow at 18%p.a?

Let the money borrowed at 14℅ be XThen money borrowed at 18% is 3500−XAccording to question,X×14100+(3500−X)×18100=525On solving this we get X=2625 and 3500−X=875So,he borrow ₹875 at rate of 18℅p.a.

Let the money borrowed at 14℅ be $X$
Then money borrowed at 18% is $3500 - X$
According to question, $X \times \frac{14}{100} +$ $(3500 - X) \times \frac{18}{100} = 525$
On solving this we get $X = 2625$ and $3500 - X = 875$
So,he borrow $₹ 875$ at rate of $18 ℅ p . a .$