A mercury barometer has a column height of $76 c m$ . What will be the height of the column if the mercury is replaced with an oil having a density of $760 k g m^{- 3}$ ? (Density of mercury is $13600 k g m^{- 3}$ )

13.6 m

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27.2 m

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76 c m

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23.8 m

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Solution

The correct option is A $13.6 m$

Liquid in barometer exert pressure on its base equal to the atmospheric pressure.

If the density of the liquid is low, more height will be required to maintain the same pressure.

So, from the formula $h = \frac{P}{ρ g}$ (from $P = ρ g h$ ) we can find height ‘h’ if density ‘ρ’ is changed, for given atmospheric pressure P.

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Similar questions

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At a given place a mercury barometer records a pressure of 0.70m of Hg . What would be the height of water column if mercury in barometer is replaced by water ? Take density of mercury to be 13.6 ×10pawer3 kg m-3 .

Q. The column of mercury in a barometer is

76 m m

of Hg. Calculate the atmospheric pressure if the density of mercury =

13600 k g m^{- 3}

. (Take

g = 10 m s^{- 2}

)

Q. The height of a mercury column in a barometer at a place is

74 c m

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5.44 g c m^{- 3}

is used then find the height of the liquid column.

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A mercury barometer has a column height of 76 cm. What will be the height of the column if the mercury is replaced with an oil having a density of 760 kg m−3? (Density of mercury is 13600 kg m−3)​

A mercury barometer has a column height of $76 c m$ . What will be the height of the column if the mercury is replaced with an oil having a density of $760 k g m^{- 3}$ ? (Density of mercury is $13600 k g m^{- 3}$ )