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Question

A mercury Celsius thermometer is transferred from melting ice to a hot liquid. The mercury rises to 910th of the distance between the two fixed points. Find the temperature of the liquid in Fahrenheit scale.

A
162F
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B
194F
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C
90F
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D
112F
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Solution

The correct option is B 194F
We know, for Celsius scale
UFP =100C, LFP =0C
Temperature of liquid given =910×(UFPLFP)=910×(1000)C=90C

Now, the temperature in Fahrenheit scale is given by
95C=F32
95×90=F32
F=194F

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