A mercury Celsius thermometer is transferred from melting ice to a hot liquid. The mercury rises to 910th of the distance between the two fixed points. Find the temperature of the liquid in Fahrenheit scale.
A
162∘F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
194∘F
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
90∘F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
112∘F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B194∘F We know, for Celsius scale
UFP =100∘C, LFP =0∘C ∴ Temperature of liquid given =910×(UFP−LFP)=910×(100−0)∘C=90∘C
Now, the temperature in Fahrenheit scale is given by 95C=F−32 ⇒95×90=F−32 ⇒F=194∘F