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Question

# A mercury manometer is used to measure the static pressure at a point in a water pipe as shown in figure. The level difference of mercury in the two limbs is 10 mm. The gauge pressure at that point is

A
1236 Pa
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B
1333 Pa
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C
Zero
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D
98 Pa
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Solution

## The correct option is A 1236 PaMethod I; Considering density of water be 1000kg/m3 and that of mercury be 13600kg/m3, Gauge pressure =(ρm−ρw)gh =(13600-1000)×9.81×10×10−3 =1236 Pa Method II: Given: Level difference of mercury in the two limbs, x=10mm Now, hw=x(ρHgρw−1)=10(136001000−1) =10×12.6=126mm of water =0.126 m of water Gauge pressure, P=ρwghw=1000×9.81×0.126 = 1236.06 = 1236 Pa

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