Question

A mercury thermometer is transferred from melting ice to a hot liquid. If the mercury rise by $\frac{4}{5}th$ of the distance between the two fixed points, then the temperature of the liquid in centrigrade and Fahrenheit scales

Answer 1

Scale length of Celsius scale is $100-0={100}^{o}C$

So mercury rises by $\frac{4}{5}$th of the initial distance.

On Celsius scale temperature will be $\frac{4}{5}\times 100={80}^{0}C$

Scale length of Fahrenheit scale is $212-32={180}^{o}F$

So mercury rises by $\frac{4}{5}$th of initial distance.

On Fahrenheit scale temperature will be=$32+$ $\frac{4}{5}\times 180={176}^{0}F$