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Question

A merry-go-round turns through 6000 degrees in 3 s from rest. _____ is the average angular speed of the ride.

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Solution

θ1=0,θ2=60 and t = 3 secs
Angular velocity = (θ2θ1)/t =60/3 = 20 degrees/sec
In radians/sec, we can write 20 degrees/sec as = 2000×π180=35radians/s

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