A message signal of $12 k H z$ and peak voltage $20 V$ is used to modulate a carrier wave of frequency $12 M H z$ and peak voltage $30 V$ . Then the modulation index is

0.32

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6.7

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0.67

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67

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Solution

The correct option is B $0.67$
Peak Voltage = $20 V$ (Message Signal)
Peak Voltage = $30 V$ (Carrier wave)

So, m(Modulation Index)= $\frac{20}{30}$
$m = 0.67$

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A message signal of 12kHz and peak voltage 20V is used to modulate a carrier wave of frequency 12MHz and peak voltage 30V. Then the modulation index is

The correct option is B 0.67Peak Voltage = 20V (Message Signal)Peak Voltage = 30V (Carrier wave)So, m(Modulation Index)=2030 m=0.67

A message signal of $12 k H z$ and peak voltage $20 V$ is used to modulate a carrier wave of frequency $12 M H z$ and peak voltage $30 V$ . Then the modulation index is

The correct option is B $0.67$
Peak Voltage = $20 V$ (Message Signal)
Peak Voltage = $30 V$ (Carrier wave)

So, m(Modulation Index)= $\frac{20}{30}$
$m = 0.67$