Question

A metal “A” reacts with a metallic chloride of “B” to give metal “B” but metallic chloride of “A” cannot give metal “A” “B” What conclusion can you draw from this?

Answer 1

Metal ‘A’ + metallic chloride ‘B' $\to$metal chloride of ‘A’ + metal ‘B’

(i) Here, we can say that metal ‘A’ is displacing chlorine from metallic chloride ‘B’.

(ii) metallic chloride of ‘A’ will not give metal ‘A’ on reaction with metal ‘B’ due to more reactivity of metal ‘A’ than chlorine.

So now, the conclusion that we can draw from this is:-

(i) metal ‘B’ is less reactive than chlorine.

(ii) metal ‘A’ is more reactive that chlorine.

(iii) It is showing displacement reaction.

For. Eg.:- $$\begin{gathered} \mathrm{Zn}\left(\mathrm{s}\right)+2\mathrm{HCl}\left(\mathrm{l}\right)\to {\mathrm{ZnCl}}_2\left(\mathrm{s}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right) \\ (\mathrm{metal}\mathrm{A})(\mathrm{metal}\mathrm{chloride}\mathrm{B})(\mathrm{metal}\mathrm{chloride}(\mathrm{hydrogen}) \\ \mathrm{of}\mathrm{metal}\mathrm{B}) \end{gathered}$$

Here, $\mathrm{Zn}$ is reacting with hydrogen chloride$\left(\mathrm{HCl}\right)$ and giving Zinc chloride$\left(\mathrm{ZnCl}\right)$ as the product.

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