268

You visited us 268 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Hydrides of Group 16

A metal A was...

Question

A metal (A) was dissolved in hot 1 : 1 $H N O_{3}$ solution. The solution was evaporated and half white crystals of B are obtained. The solution of B gave a brick red precipitate with $K_{2} C r O_{4}$ and a reddish yellow precipitate with $K I$ . The metal when melted and cooled showed the phenomenon of spitting

To the solution of B, add excess of $N H_{4} O H$ followed by glucose solution. The solution is heated over a hot water both. This gives:

a red precipitate of

C u_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a white precipitate of

P b N O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a black and white precipitate due to

H g

and

H g (N H_{2}) C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a black precipitate due to formation of silver on agitating the solution in the test tube.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D a black precipitate due to formation of silver on agitating the solution in the test tube.
$A g N O_{3} a q . N H_{3} + g l u c o s e - --------- \to A g ↓ (B l a c k p r e c i p i t a t e)$

Suggest Corrections

Similar questions

Q. A metal (A) was dissolved in hot 1 : 1

H N O_{3}

solution. The solution was evaporated and half white crystals of B are obtained. The solution of B gave a brick red precipitate with

K_{2} C r O_{4}

and a reddish yellow precipitate with

K I

. The metal when melted and cooled showed the phenomenon of spitting

To the solution of B, add excess of

N H_{4} O H

followed by glucose solution. The solution is heated over a hot water both. This gives:

Q. A metal (A) was dissolved in hot 1 : 1

H N O_{3}

solution. The solution was evaporated and half white crystals of B are obtained. The solution of B gave a brick red precipitate with

K_{2} C r O_{4}

and a yellow precipitate with KI. The metal when melted and cooled showed the phenomenon of spitting.

To the solution of B, addition of NaOH gives a brown precipitate. The brown precipitate on strong heating gives

Q. A colourless aqueous solution contain nitrates of two metal, when it is added to an aqueous solution of

N a C l

, a white precipitate ws formed. This precipitate was found to be partially soluble in hot water to give a residue

P

and a solution

Q

. The residue

P

was solublein aq. in

N H_{3}

and also in excess sodium thiosulfate. The hot solution

Q

gave a yellow precipitate with

K I

. The metals

X

and

Y

, respectively, are:

Q. When

A g N O_{3}

is treated with hypo solution, a white ppt of A is formed. This gets dissolved when excess of hypo solution is added due to the formation of compound B. Precipitate A on boiling with water turns black due to the formation of C. Find the incorrect option:

An aqueous solution of salt (A), gives white crystalline precipitate (B) with NaCl solution. The filtrate gives a black precipitate (C) when

H_{2} S

is passed through it. Compound (B) is dissolves in hot water and the solution gives a yellow precipitate (D) on treating with NaI and cooling. The compound (A) does not give any gas with dilute HCl but liberates reddish brown gas on heating.

Compound (B) is:

Join BYJU'S Learning Program

The correct option is D a black precipitate due to formation of silver on agitating the solution in the test tube.AgNO3aq. NH3+glucose−−−−−−−−−−→Ag↓(Black precipitate)

The correct option is D a black precipitate due to formation of silver on agitating the solution in the test tube.
$A g N O_{3} a q . N H_{3} + g l u c o s e - --------- \to A g ↓ (B l a c k p r e c i p i t a t e)$