A metal ball falls from a height of 32 m on a steel plate. If the coefficient of restitution is 0.5, to what height will the ball rise after the second bounce

2 m

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4 m

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8 m

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16 m

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Solution

The correct option is A
2 m

$h_{n} = h e^{2 n} = 32 {(\frac{1}{2})}^{4} = \frac{32}{16} = 2 m (h e r e n = 2, e = \frac{1}{2})$

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A metal ball falls from a height of 32 m on a steel plate. If the coefficient of restitution is 0.5, to what height will the ball rise after the second bounce

The correct option is A 2 m hn=he2n=32(12)4=3216=2m (here n=2, e=12)

The correct option is A
2 m

$h_{n} = h e^{2 n} = 32 {(\frac{1}{2})}^{4} = \frac{32}{16} = 2 m (h e r e n = 2, e = \frac{1}{2})$