A metal ball immersed in alcohol weighs W1 at 0∘C and W2 at 59∘C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol, it can be shown that
W1 < W2
As the coefficient of cubical expansion of metal is less as compared to the coefficient of cubical expansion of liquid, we may neglect the expansion of metal ball. So when the ball is immersed in alcohol at 0∘C, it displaces some volume V of alcohol at 0ºC and has weight W1.
∴ W1=W0−vρ0g
where W0 = weight of ball in air
Similarly , W2=W0−Vρ50g
where ρ0 = density of alcohol at 0∘C
and ρ50 = density of alcohol at 50∘C
As ρ50<ρ0,⇒W2>W1orW1<W2