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Question

A metal ball immersed in alcohol weighs W1 at 0C and W2 at 59C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol, it can be shown that


A

W1 > W2

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B

W1 = W2

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C

W1 < W2

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D

W2 = (W1/2)

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Solution

The correct option is C

W1 < W2


As the coefficient of cubical expansion of metal is less as compared to the coefficient of cubical expansion of liquid, we may neglect the expansion of metal ball. So when the ball is immersed in alcohol at 0C, it displaces some volume V of alcohol at 0ºC and has weight W1.

W1=W0vρ0g

where W0 = weight of ball in air

Similarly , W2=W0Vρ50g

where ρ0 = density of alcohol at 0C

and ρ50 = density of alcohol at 50C

As ρ50<ρ0,W2>W1orW1<W2


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