A metal ball of mass 2 kg is dropped in water of mass 8 kg at 12 -C- The final temperature of water is 48 -C -Find the temperature of the object when its specific heat capacity is 130J kg -1 K -1-

The correct option is C 128 ^∘C Explanation: let the temperature of the ball be #160; t ^∘ #160;C Fall in temperature of the ball #160;t 48 ...

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Byju's Answer

Standard X

Physics

Specific Heat Capacity

A metal ball ...

Question

A metal ball of mass $2$ kg is dropped in water of mass $8$ kg at $12^{\circ} C$ . The final temperature of water is $48^{\circ} C$ .Find the temperature of the object when its specific heat capacity is $130 J {k g}^{- 1} K^{- 1}$ .

150^{\circ} C

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246^{\circ} C

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128^{\circ} C

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156^{\circ} C

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Solution

The correct option is C $128^{\circ} C$
Explanation: let the temperature of the ball be $t^{\circ} C$
Fall in temperature of the ball $t - 48^{\circ} C$
Rise in temperature of the water $48 - 12 = 36^{\circ} C$
Heat given by the ball $= 2 \times 130 \times (t - 48) J$
Heat energy taken by water $= 8 \times 130 \times 20 = 20800 J$
$= 48 - 12$ ,
Heat given by the ball = Heat energy taken by water
$2 \times 130 \times (t - 48) = 20800$
$260 t - 12480 = 20800$
$260 t = 33280$
$t = 128^{\circ} C$

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A metal ball of mass 2 kg is dropped in water of mass 8 kg at 12∘C. The final temperature of water is 48∘C .Find the temperature of the object when its specific heat capacity is 130Jkg−1K−1.

A metal ball of mass $2$ kg is dropped in water of mass $8$ kg at $12^{\circ} C$ . The final temperature of water is $48^{\circ} C$ .Find the temperature of the object when its specific heat capacity is $130 J {k g}^{- 1} K^{- 1}$ .