A metal ball of mass 2kg moving with a velocity of 36 km/h has a head on collision with a stationary ball of mass 3kg. If after the collision, the two balls move together, the loss in kinetic energy due to collision is.
A
140J
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B
100J
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C
60J
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D
40J
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Solution
The correct option is C60J Apply conservation of momentum, m1v1=(m1+m2)v v=m1v1(m1+m2) Here v1=36km/hr=10m/s, m1=2kg,m2=3kg v=10×25=4m/s K.E. (initial) =12×2×(10)2=100J K.E. (Final) =12×(3+2)×(4)2=40J Loss in K.E. =100−40=60J Alternatively use the formula −ΔEk=12m1m2(m1+m2)(u1−u2)2