A metal ball of mass 2 kg moving with speed of 36 km/hr is having a collision with a stationary ball of mass 3 kg. If after collision, both the balls move together, the loss in kinetic energy due to collision is :
A
80J
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B
40J
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C
60J
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D
160J
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Solution
The correct option is B60J Let v be the common velocity. Applying conservation of momentum 2×10+3×0=(2+3)v v=10×25=4m/sec [36km/hour=10m/sec] Initial Energy =12×2×(10)2+0=100J Final Energy =12×5×4×4=40J Loss of energy =100−40=60 joule