A metal ball of mass $2 k g$ is allowed to fall freely from rest from a height of $5 m$ above the ground (Take $g = 10 m s^{- 2}$ ). What is the kinetic energy of the ball just before it hits the ground?

10 J

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100 J

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50 J

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0 J

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Solution

The correct option is B $100 J$
When ball is at rest it will only have $P o t e n t i a l E n e r g y$ that is,

$P . E = m g h$

$m = 2 k g; h = 5 m$

$P . E = 2 \times 10 \times 5 = 100 J$

This is the total energy as $K . E$ is zero when the ball is at maximum height that is when it is at $5 m$ . Hence when the ball reaches the ground $P . E$ becomes zero because of zero height.At this point,the total energy is equal to the $K . E$ that is $K . E = 100 J$ .

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Similar questions

A metal ball of mass 2 kg is allowed to fall freely from rest from a height of 5 m above the ground.

(a) Taking g=10 m $s^{- 2}$ ,calculate:

(i) the potential energy possessed by the ball when it is initially at rest.

(ii) the kinetic energy of the ball just before it hits the ground?

(b) What happens to the mechanical energy after the ball hits the ground and comes to rest?

Q. A metal ball of mass

2 k g

is allowed to fall freely from rest from a height of

5 m

above the ground (Take

g = 10 m s^{- 2}

). After the ball hits the ground and comes to rest, mechanical energy is converted to:

Q. A metal ball of mass

2 k g

is allowed to fall freely from rest from a height of

5 m

above the ground (Take

g = 10 m s^{- 2}

). Calculate the potential energy possessed by the ball when initially at rest.

We know that If a ball of mass $1 k g$ is kept at a height $10 m$ possess potential energy $m g h$ i.e. $(1 \times 10 \times 10) = 100$ J. (Taking earth surface as reference, where m = mass of object, g = acceleration due to gravity, h = height of object from earth surface.) what will be the kinetic energy of the ball when the ball is allowed to freely fall from a height $10 m$ just before it hits the ground? (take g = 10 $m / s^{2}$ and neglect air drag)

A ball of mass 200g falls from a height of 5m. What is its kinetic energy when it just reaches the ground. (Take $g = 9.8 m s^{- 2}$ )

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A metal ball of mass 2kg is allowed to fall freely from rest from a height of 5m above the ground (Take g=10ms−2). What is the kinetic energy of the ball just before it hits the ground?

A metal ball of mass $2 k g$ is allowed to fall freely from rest from a height of $5 m$ above the ground (Take $g = 10 m s^{- 2}$ ). What is the kinetic energy of the ball just before it hits the ground?