Given: A metal ball of mass 400g and at 600oC is placed on the block of ice, when 428g of ice melts. If the specific heat capacity of metal ball is 0.6J/(goC)
To find the specific latent heat of ice.
Solution:
As per the given criteria,
Mass of the metal ball, mb=400g
Temperature of the metal ball, Tb=600∘C
Mass of melted ice, mi=428g
Specific heat of metal ball, cb=0.6J/(goC)
As the block does not melt completely therefore final temperature is zero degree Celsius.
Heat gained by ice to melt =miL=428×L
Heat lost by metal ball =mbcbTb=400×0.6×600=144000J
We know,
Heat gained = heat lost
Therefore, 428×L=144000⟹L=144000428=336.4J/g
is the specific latent heat of ice.