wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A metal ball of mass 400g and at 600C is placed on a block of ice when 428g of ice melts. If the specific heat capacity of the metal ball is 0.6Jg-1C-1, calculate the specific latent heat of ice.


Open in App
Solution

Step 1: Given data

  1. The mass of a metal ball is 400g and placed on a block of ice when 428g of ice melts.
  2. And the sp. heat capacity of the metal ball is 0.6Jg-1C-1.

Step 2: Calculating the heat gained by ice to melt

Let the specific latent heat of ice is LJg-1C-1

The amount of heat required to melt the ice is

=massofice×specificlatentheatofice=428×L

Step 3: Calculating the Heat lost by the metal ball

The heat lost by the ball

massofmetalball×specificheatcapacityofball×temperaturedifference=400×0.6×(600-0)Jule=144000Jule

Step 4: Calculating the sp. latent heat of ice

The main theorem of calorimetry

heatgain=heatlost428×L=144000L=144000428L=336.4Jg-1

Hence, the specific latent heat of ice is 336.4Jg-1.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Messengers of Heat
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon